Indexerror pop index out of range in python

pop( randint( 0, len( deck) - 1) ). Though it' s faster if you save that value somewhere. But that also points to a problem that your deck has a problem. Are you for loops in the deck creation. pop( ) takes the index of an element to remove, not the item to remove. remove( ) instead. l= range( 8) > > > l [ 0, 1, 2, 3, 4, 5, 6, 7] > > > l. pop( 4) # item at index 4 4 > > > l [ 0, 1, 2, 3, 5, 6, 7] > > > l. pop( - 1) # item at end. l= [ ] > > > try:. except IndexError:. print " sorry - - can' t pop that". sorry - - can' t pop that. Navin Kabra, Python' s my primary language for development for last 2 years. And if you' ve already popped at least one value out of this list earlier, List.

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    Index range indexerror

    pop( 8) is going to fail with an IndexError because List does not have 9. What does the error: " IndexError: list index out of range" imply in the following piece of code? You are removing elements from the list as you are iterating over them, this causes the list to shrink in size during iteration, but the iteration would still continue for the length of the original list, hence causing such InderError. There are problems with your code, for example in this selection they are all present: result. append( left[ 0] ) left = left. This should be: result. The problems are: Python lists use 0- based indexing so. 引数を省略して位置を指定しない場合は、 末尾( 最後) の要素を削除する。 print( l. pop( ) ) # 9 print( l) # [ 1, 2, 3, 5, 6, 7]. source: list_ remove_ item. 存在しない位置を指定 するとエラーになる。 IndexError: pop index out of range. For instance, when you find that 21 is above the average and try to remove it with L. pop( 21), it looks for the 21st item in the list.

    Since there are not that many items, you get an IndexError. remove( 21) instead of pop( ) to. Im getting an Index Error on Line 28 that says ' IndexError: pop index out of range' I have no idea how to fix this. I' m also open to other suggestions for making my code better. By the way my program isn' t finished yet.